Probabilty model cont.

Binomial probabilities

When we are willing to assume we have a binomial random process, we can apply a few probability rules to help us calculate different probabilities. Under the null model, we assume that the number of "top down" outcomes in the toast dropping process will follow a binomial distribution with n = 10 and probability of success = 0.50.

For example, to find the probability of the outcome: SSSFSSFSSFF,

Under the null model, P(S) = 0.50P(success) = 0.50
The trials are independent so we can multiply these probabilities together.P(SSSFSSFSSFF) = (.5)... (.5) = (.5)10
We can count all of the possible outcomes have 6 successes and 4 failures = "10 choose 4"C(10,4) = 10!/(6! 4!) = 210
These 210 outcomes are mutually exclusive so we can add together the probabilities for all of those possible outcomes with 4 successes.210 x (.510) = .205

In other words, P(4 successes and 6 failures in 10 tosses) = 0.205.

But this isn't quite our p-value yet. To be the p-vaue we want P(4 or fewer successes in 10 tosses).

P(4 or fewer) = C(10,4)(.510) + C(10,3)(.510) + C(10,2)(.510) + C(10,1)(.510) + C(10,0)(.510)

Which a calculator or computer will tell us equals 0.3770.



In general

Let π represent the probability of success and x the number of successes:

P(X = x) = C(n, x)x πx(1-π)n-x

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